4x^2+2x-53130=0

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Solution for 4x^2+2x-53130=0 equation:



4x^2+2x-53130=0
a = 4; b = 2; c = -53130;
Δ = b2-4ac
Δ = 22-4·4·(-53130)
Δ = 850084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{850084}=922$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-922}{2*4}=\frac{-924}{8} =-115+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+922}{2*4}=\frac{920}{8} =115 $

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